UVA Problem 10370 (Above Average) Solution

Problem Solving, UVa

#include <stdio.h>

#include <math.h>

int a[2000];

int main()

{

    int t,n,i,j,sum,count,avg,ans;

    scanf("%d",&t);

    while(t--)

    {  

        sum=0,count=0;

       

        scanf("%d",&n);

       

        for(i=0;i<n;i++)

        {

            scanf("%d",&a[i]);

        }

        for(i=0;i<n;i++)

        {

        sum+=a[i];

       

        }

        avg=sum/n;

       

        for(i=0;i<n;i++)

        {

       

        if(a[i]>avg)

        {

            count++;

        }

       

        }

        printf("%.3f%%\n",((float)count/(float)n)*100);

    }

    return 0;

}

 

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