## Timus Problem 1001 (Reverse Root) Solution

Timus Problem 1001(Reverse Root) : Reverse Root is a mathematical problem. To read details : http://acm.timus.ru/problem.aspx?space=1&num=1001 Proplem description: This is a straightforward problem.Just do square root. Problem Solution: #include...

## Timus Problem 1005 (Stone pile) Solution

Timus Problem 1005 (Stone pile): This problem is for beginner in timus online judge. Problem details link : http://acm.timus.ru/problem.aspx?space=1&num=1005 Problem Description: just find the minimal difference among a value range. Usage Tips: >> Right...

## Timus Problem 1009(K-based Numbers) Solution

Problem details link: http://acm.timus.ru/problem.aspx?space=1&num=1009﻿ Problem Description: This is a straightforward problem check validity of K-based numbers. Problem Solution: #include <stdio.h> int main() { int m[1009],n,k; scanf("%d...

## Timus Problem 1025 (Democracy in Danger) Solution

Timus problem 1025 Democracy in Danger : This problem is for beginner. Problem Details: http://acm.timus.ru/problem.aspx?space=1&num=1025 Problem Description: This is a Straightforward problem. Timus Problem 1025 Solution #include<stdio.h> int main() { int...

## Timus Problem 1064(Binary Search) Solution

Problem 1064 Binary Search details description : http://acm.timus.ru/problem.aspx?space=1&num=1064 Timus Problem 1064 Solution : #include <stdio.h> int main() { int n = 1; while(n <= 100) { printf("%d\n", n); n++; if(n > 10) { break; } n = 200; while(n...

## Timus Problem 1068 Solution

Timus Problem 1068 Solution #include <stdio.h> #include <stdlib.h> long int sum[10000]; int a[10000]; int main() { int i,n; sum[0]=1; scanf("%d",&n); for(i=0;i<=n;i++){ scanf("%d",&a[i]);} for(i=0;i<=n;i++){ sum[i]+=a[i];...

## Timus Problem 1083 Solution

Timus Problem 1083 Solution #include <stdio.h> int main() { char ch; int n,k=0,f=1; scanf("%d %c",&n,&ch); if(ch=='!'){ printf("%c",ch); k++;} else if(ch=='\n') printf("%c",ch);{ break;} for(n=1;n<=10;n++) f*=f*(n-2k); if(f<=0){ break; }...

## Timus Problem 1086 Solution

Timus Problem 1086 Solution #include <iostream> #include <stdio.h> using namespace std; bool flag[20000005]; int primes[20000005]; int cnt; void sieve(int n) { cnt=0; primes[cnt++] = 2; for(int i=3; i<=n; i+=2) { if(flag[i] == 0) { primes[cnt++] = i;...

## Timus Problem 1100 Solution

#include <stdio.h> int main() { int i,swap,j,n,l,sum=0,k,ara[100][100]; scanf("%d",&n); for(i=0;i<n;i++){ scanf("%d %d",&ara[i][j]); } for(i=0;i<n;i++) { for(j=0;j<n-i;j++) { if(ara[j]<ara[j+1]) { ara[i]=ara[i+1]; ara[i+1]=ara[j];...

## Timus Problem 1104 Solution

#include <stdio.h> #include <ctype.h> int main() { long num=0,k,v,max=1; char ch; ch=getchar(); while(ch!=EOF) { if(isdigit(ch)) v=ch-'0'; else v=ch-'A'+10; num+=v; if(v>max) max=v; ch=getchar(); } for(k=max;k<36;k++) if(num%k==0) break; if(k<36)...

## Timus Problem 1110 Solution

Timus Problem 1110 Solution #include<stdio.h> #include<math.h> #include<string.h> #define fi(a, b) for(int i=a; i<b; i++) #define fj(a, b) for(int j=a; j<b; j++) #define fk(a, b) for(int k=a; k<b; k++) #define sf scanf #define pf printf...

## Timus Problem 1120 Solution

Timus Problem 1120 Solution #include <stdio.h> int main(void){ unsigned n,p,s; scanf("%u",&n); for(p=44720;n<(s=(p*(p+1))>>1)||(n-s)%p;p--); printf("%u %u\n",1+(n-s)/p,p); return 0; }

## Timus Problem 1196 Solution

Timus Problem 1196 Solution #include <stdio.h> int b[1000000]; int a[15000]; int main() { int i,j,k,n,m,c=0,first,last,mid; scanf("%d\n",&n); for(i=0;i<n;i++) { scanf("%d",&a[i]); } scanf("%d\n",&m); for(i=0;i<m;i++) { scanf("%d",&b[i]); }...

## Timus Problem 1197 Solution

Timus Problem 1197 Solution #include <stdio.h> #include <conio.h> int main() { int X, Z,t; char Y; scanf("%d",&t); while(t--){ scanf("%c%d",&Y, &Z); switch ( Y ) { case 'a': Y = 1; break; case 'b': Y = 2; break; case 'c': Y = 3; break;...

## Timus Problem 1209 Solution

#include<stdio.h> #include<math.h> unsigned long a[70000]; int main() { unsigned long i,k,n; long double l; scanf("%lu\n",&n); for(i=0;i<n;i++) { scanf("%lu",&a[i]); } for(i=0;i<n;i++) { l=((sqrt(-7+8*a[i])-1)/ 2); k=l; if(l==k) printf("1 ");...

## Timus Problem 1224 Solution

Timus Problem 1224 Solution #include <stdio.h> int main() { long int n, m,o; scanf("%ld%ld", &n, &m); o=n <= m ? 2 * n - 2 : 2 * m - 1; printf("%u",o); }

## Timus Problem 1225 Solution

Timus Problem 1225 Solution #include <stdio.h> int main() { int n, m; scanf("%d", &n); m=2*n-2; printf("%d",m); }

## Timus Problem 1234 Solution

Timus Problem 1234 Solution #include <stdio.h> int a[10001]; int main() { int ans=0,ans1=0,k,n,i; scanf("%d %d",&n,&k); for(i=0;i<n;i++){ scanf("%d",&a[i]); } if(a[i]<k){ ans+=k-a[i]; } else{ ans1+=a[i]-k; } printf("%d %d",ans,ans1); return 0;...

## Timus Problem 1243 Solution

#include <stdio.h> int main() { long long int a,b,l=0,r=0; scanf("%lld",&a); r=a%7; printf("minr=%lld",r); return 0; }

## Timus Problem 1263 Solution

Timus Problem 1263 Solution #include <stdio.h> double a[10004]; int main() { int i,m,n,l,o; double d=0; scanf("%d %d",&n,&m); l=m; while(m--) { scanf("%d",&o); a[o]++; } for(i=0;i<n;i++) { d=(a[i]/l)*100; printf("%2.2lf%%\n",d); } return 0; }...

## Frequency Word for IELTS Listening

Frequency Word for IELTS Listening School a. Library  WordSentence1. Shelf 2. Librarian 3. The stacks 4. Return 5. Fine 6. Magazine 7. Copier  8. Overdue  9. Reading room  10. Reference...

## Chapter 8: Gantt chart Project Development in SDLC

Gantt chart Project DevelopmentSchedule (project management) The project scheduleis the tool that communicates what work needs to be performed, which resources of the organization will perform the work and the timeframes in which that work needs to be performed....

## Chapter 6: Data Flow Diagram in Software Development Life Cycle.

Data Flow Diagram What is DFD? A data flow diagram (DFD) is a graphical representation of the "flow" of data through an information system, modelling its process aspects.A DFD is often used as a preliminary step to create an overview of the system, which can later be...

## Chapter 5: System request on SDLC

System Request In most organizations, project initiation begins by preparing a  system request. A  system request is a document that describes the business reasons for building a system and the value that the system is expected to provide.The project sponsor...