Timus Problem 1820 Solution

Timus Problem Solution

Timus Problem 1820 Solution

#include <stdio.h>

int main()

{

    int n,k,t;

    scanf("%d %d",&n,&k);

    if(n<k){

        printf("2");}

        else{

            if(2*n%k==1){

            t=2*n/k+1;

            }

            else{

                t=2*n/k;

            }

            printf("%d",t);

    }

    return 0;



}

 

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