Timus Problem 1068 Solution

Timus Problem Solution

Timus Problem 1068 Solution

#include <stdio.h>

#include <stdlib.h>

    long int sum[10000];

int a[10000];

int main()

{

    int i,n;

    sum[0]=1;

    scanf("%d",&n);

    for(i=0;i<=n;i++){

        scanf("%d",&a[i]);}

    for(i=0;i<=n;i++){

    sum[i]+=a[i];

    printf("%ld",sum[i]);}

}

 

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