Timus Problem 1001(Reverse Root) :
Reverse Root is a mathematical problem.
To read details : http://acm.timus.ru/problem.aspx?space=1&num=1001
Proplem description: This is a straightforward problem.Just do square root.
Problem Solution:
#include <stdio.h>
#include <math.h>
int main()
{
double a[100],b[100];
int i,j,swap,n;
scanf("%d",&n);
for(i=0;i<n;i++){
scanf("%lf",&a[100]);
}
for(i=0;i<n;i++){
b[j]=sqrt(a[i]);
j++;}
for(i=0;i<j;i++){
for(j=0;j<i;j++){
if(b[j]==b[j+1]||b[j]>b[j+1]||b[j]<b[j+1]){
swap=b[j];
b[j]=b[j+1];
b[j+1]=swap;}
}
}
for(i=0;i<n;i++){
printf("%.4lf\n",b[i]);
}
return 0;
}
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