Timus Problem 1197 Solution

Timus Problem Solution

 

Timus Problem 1197 Solution

#include <stdio.h>

#include <conio.h>



int main()

{

    int X, Z,t;

     char Y;

        scanf("%d",&t);

        while(t--){

            scanf("%c%d",&Y, &Z);

       switch ( Y )

        {

        case 'a': Y = 1;

            break;

        case 'b': Y = 2;

            break;

        case 'c': Y = 3;

            break;

        case 'd': Y = 4;

            break;

        case 'e': Y = 5;

            break;

        case 'f': Y = 6;

            break;

        case 'g': Y = 7;

            break;

        case 'h': Y = 8;

            break;

        default:

            break;

        }



        if (Y == 1 && Z == 1 || Y == 1 && Z == 8 || Y == 8 && Z == 1 || Y == 8 && Z == 8) {

        printf("2");

    } else if(Y == 1 && Z == 2 || Y == 1 && Z == 7 || Y == 2 && Z == 1 || Y == 2 && Z == 8 || Y == 7 && Z == 1 || Y == 7 && Z == 8 || Y == 8 && Z == 2 || Y == 8 && Z == 7) {

            printf("3");

        } else if (Y == 1 && Z == 3 || Y == 1 && Z == 4 || Y == 1 && Z == 5 || Y == 1 && Z == 6 || Y == 8 && Z == 3 || Y == 8 && Z == 4 || Y == 8 && Z == 5 || Y == 8 && Z == 6 || Z == 1 && Y == 3 || Z == 1 && Y == 4 || Z == 1 && Y == 5 || Z == 1 && Y == 6 || Z == 8 && Y == 3 || Z == 8 && Y == 4 || Z == 8 && Y == 5 || Z == 8 && Y == 6 || Y == 2 && Z == 2 || Y == 2 && Z == 7 || Y == 7 && Z == 2 || Y == 7 && Z == 7) {

                printf("4");

            } else if(Y == 2 && Z == 3 || Y == 2 && Z == 4 || Y == 2 && Z == 5 || Y == 2 && Z == 6 || Y == 7 && Z == 3 || Y == 7 && Z == 4 || Y == 7 && Z == 5 || Y == 7 && Z == 6 || Z == 2 && Y == 3 || Z == 2 && Y == 4 || Z == 2 && Y == 5 || Z == 2 && Y == 6 || Z == 7 && Y == 3 || Z == 7 && Y == 4 || Z == 7 && Y == 5 || Z == 7 && Y == 6) {

                    printf("6");

                } else if(Y == 3 && Z == 3 || Y == 3 && Z == 4 || Y == 3 && Z == 5 || Y == 3 && Z == 6 || Y == 4 && Z == 3 || Y == 4 && Z == 4 || Y == 4 && Z == 5 || Y == 4 && Z == 6 || Y == 5 && Z == 3 || Y == 5 && Z == 4 || Y == 5 && Z == 5 || Y == 5 && Z == 6 || Y == 6 && Z == 3 || Y == 6 && Z == 4 || Y == 6 && Z == 5 || Y == 6 && Z == 6) {

                        printf("8");

                   } }

                   return 0;



}

 

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