URI Problem (Average 3) 1040:
Average 3 is a basic problem on URI online judge for novice problem solver.
You can find details on this Link.
import java.text.DecimalFormat;
import java.util.Scanner;
/**
* @Author : Muhammad Harun-Or-Roshid
* @Date : Oct 10, 2016
* @Time : 9:09:13 PM
*/
public class Uri1040 {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
double n1, n2, n3, n4, n5, average, recalculate;
int a = 2, b = 3, c = 4, d = 1;
n1 = sc.nextDouble();
n2 = sc.nextDouble();
n3 = sc.nextDouble();
n4 = sc.nextDouble();
average = toDouble(((n1 * a) + (n2 * b) + (n3 * c) + (n4 * d)) / (a + b + c + d));
System.out.println("Media: " + average);
if (average >= 7.0) {
System.out.println("Aluno aprovado.");
} else if (average < 5.0) {
System.out.println("Aluno reprovado.");
} else if(average >=5.00 && average <= 6.9){
System.out.println("Aluno em exame.");
n5 = sc.nextDouble();
System.out.println("Nota do exame: " + n5);
recalculate = toDouble((n5 + average) / 2);
if (recalculate >= 5.0) {
System.out.println("Aluno aprovado.");
} else if (recalculate <= 4.9) {
System.out.println("Aluno reprovado.");
}
System.out.println("Media final: " + recalculate);
}
}
private static double toDouble(double x){
DecimalFormat format = new DecimalFormat("#0.0");
return Double.valueOf(format.format(x));
}
}