Part 8: Strings in C Programming Language

C Programming | 0 comments

C- Strings

Strings are actually one-dimensional array of characters terminated by a null character ‘\0’. Thus a null-terminated string contains the characters that comprise the string followed by a null.

The following declaration and initialization create a string consisting of the word “Hello”. To hold the null character at the end of the array, the size of the character array containing the string is one more than the number of characters in the word “Hello.”

char greeting[6] = {'H', 'e', 'l', 'l', 'o', '\0'};

If you follow the rule of array initialization then you can write the above statement as follows −

char greeting[] = "Hello";

Following is the memory presentation of the above defined string in C/C++ −

String Presentation in C/C++

Actually, you do not place the null character at the end of a string constant. The C compiler automatically places the ‘\0’ at the end of the string when it initializes the array. Let us try to print the above mentioned string −

#include <stdio.h>
 int main () {
 char greeting[6] = {'H', 'e', 'l', 'l', 'o', '\0'};
 printf("Greeting message: %s\n", greeting );
 return 0; 
}

When the above code is compiled and executed, it produces the following result −

Greeting message: Hello

C supports a wide range of functions that manipulate null-terminated strings −

Sr.No. Function & Purpose
1 strcpy(s1, s2);

Copies string s2 into string s1.

2 strcat(s1, s2);

Concatenates string s2 onto the end of string s1.

3 strlen(s1);

Returns the length of string s1.

4 strcmp(s1, s2);

Returns 0 if s1 and s2 are the same; less than 0 if s1<s2; greater than 0 if s1>s2.

5 strchr(s1, ch);

Returns a pointer to the first occurrence of character ch in string s1.

6 strstr(s1, s2);

Returns a pointer to the first occurrence of string s2 in string s1.

The following example uses some of the above-mentioned functions:

#include <stdio.h>
 #include <string.h> 
int main () {
 char str1[12] = "Hello";
 char str2[12] = "World"; 
char str3[12];
 int len ; /* copy str1 into str3 */
 strcpy(str3, str1);
 printf("strcpy( str3, str1) : %s\n", str3 ); /* concatenates str1 and str2 */
 strcat( str1, str2); 
printf("strcat( str1, str2): %s\n", str1 ); /* total lenghth of str1 after concatenation */ 
len = strlen(str1);
 printf("strlen(str1) : %d\n", len );
 return 0;
 }

When the above code is compiled and executed, it produces the following result −

strcpy( str3, str1) : Hello strcat( str1, str2): HelloWorld strlen(str1) : 10

C- Structures

Arrays allow to define type of variables that can hold several data items of the same kind. Similarly structure is another user defined data type available in C that allows to combine data items of different kinds.

Structures are used to represent a record. Suppose you want to keep track of your books in a library. You might want to track the following attributes about each book −

  • Title
  • Author
  • Subject
  • Book ID

Defining a Structure

To define a structure, you must use the struct statement. The struct statement defines a new data type, with more than one member. The format of the struct statement is as follows −

struct [structure tag] {

   member definition;
   member definition;
   ...
   member definition;
} [one or more structure variables];

The structure tag is optional and each member definition is a normal variable definition, such as int i; or float f; or any other valid variable definition. At the end of the structure’s definition, before the final semicolon, you can specify one or more structure variables but it is optional. Here is the way you would declare the Book structure −

struct Books {
   char  title[50];
   char  author[50];
   char  subject[100];
   int   book_id;
} book;

Accessing Structure Members

To access any member of a structure, we use the member access operator (.). The member access operator is coded as a period between the structure variable name and the structure member that we wish to access. You would use the keyword struct to define variables of structure type. The following example shows how to use a structure in a program:

#include <stdio.h>
#include <string.h>
 
struct Books {
   char  title[50];
   char  author[50];
   char  subject[100];
   int   book_id;
};
 
int main( ) {

   struct Books Book1;        /* Declare Book1 of type Book */
   struct Books Book2;        /* Declare Book2 of type Book */
 
   /* book 1 specification */
   strcpy( Book1.title, "C Programming");
   strcpy( Book1.author, "Nuha Ali"); 
   strcpy( Book1.subject, "C Programming Tutorial");
   Book1.book_id = 6495407;

   /* book 2 specification */
   strcpy( Book2.title, "Telecom Billing");
   strcpy( Book2.author, "Zara Ali");
   strcpy( Book2.subject, "Telecom Billing Tutorial");
   Book2.book_id = 6495700;
 
   /* print Book1 info */
   printf( "Book 1 title : %s\n", Book1.title);
   printf( "Book 1 author : %s\n", Book1.author);
   printf( "Book 1 subject : %s\n", Book1.subject);
   printf( "Book 1 book_id : %d\n", Book1.book_id);

   /* print Book2 info */
   printf( "Book 2 title : %s\n", Book2.title);
   printf( "Book 2 author : %s\n", Book2.author);
   printf( "Book 2 subject : %s\n", Book2.subject);
   printf( "Book 2 book_id : %d\n", Book2.book_id);

   return 0;
}

 

When the above code is compiled and executed, it produces the following result −
Book 1 title : C Programming
Book 1 author : Nuha Ali
Book 1 subject : C Programming Tutorial
Book 1 book_id : 6495407
Book 2 title : Telecom Billing
Book 2 author : Zara Ali
Book 2 subject : Telecom Billing Tutorial
Book 2 book_id : 6495700

Structures as Function Arguments

You can pass a structure as a function argument in the same way as you pass any other variable or pointer.

#include <stdio.h>
 #include <string.h>
 struct Books { 
char title[50]; 
char author[50];
 char subject[100];
 int book_id; }; /* function declaration */

 void printBook( struct Books book ); 
int main( ) { 
struct Books Book1; /* Declare Book1 of type Book */ 
struct Books Book2; /* Declare Book2 of type Book */
 /* book 1 specification */ 
strcpy( Book1.title, "C Programming"); 
strcpy( Book1.author, "Nuha Ali"); 
strcpy( Book1.subject, "C Programming Tutorial"); 
Book1.book_id = 6495407; /* book 2 specification */
 strcpy( Book2.title, "Telecom Billing"); 
strcpy( Book2.author, "Zara Ali");
strcpy( Book2.subject, "Telecom Billing Tutorial"); 
Book2.book_id = 6495700; /* print Book1 info */
 printBook( Book1 ); /* Print Book2 info */ 
printBook( Book2 ); 
return 0; 
} 
void printBook( struct Books book ) {
 printf( "Book title : %s\n", book.title);
 printf( "Book author : %s\n", book.author);
 printf( "Book subject : %s\n", book.subject); 
printf( "Book book_id : %d\n", book.book_id); 
}

When the above code is compiled and executed, it produces the following result −

Book title : C Programming
Book author : Nuha Ali
Book subject : C Programming Tutorial
Book book_id : 6495407
Book title : Telecom Billing
Book author : Zara Ali
Book subject : Telecom Billing Tutorial
Book book_id : 6495700

Pointers to Structures

You can define pointers to structures in the same way as you define pointer to any other variable −

struct Books *struct_pointer;

Now, you can store the address of a structure variable in the above defined pointer variable. To find the address of a structure variable, place the ‘&’; operator before the structure’s name as follows −

struct_pointer = &Book1;

To access the members of a structure using a pointer to that structure, you must use the → operator as follows −

struct_pointer->title;

Let us re-write the above example using structure pointer.

#include <stdio.h> 
#include <string.h> 
struct Books { 
char title[50]; 
char author[50]; 
char subject[100]; 
int book_id; }; /* function declaration */ 

void printBook( struct Books *book );
 int main( ) { 
struct Books Book1; /* Declare Book1 of type Book */ 
struct Books Book2; /* Declare Book2 of type Book */
 /* book 1 specification */
 strcpy( Book1.title, "C Programming");
 strcpy( Book1.author, "Nuha Ali");
 strcpy( Book1.subject, "C Programming Tutorial");
 Book1.book_id = 6495407; /* book 2 specification */
 strcpy( Book2.title, "Telecom Billing");
 strcpy( Book2.author, "Zara Ali");
 strcpy( Book2.subject, "Telecom Billing Tutorial");
 Book2.book_id = 6495700; /* print Book1 info by passing address of Book1 */ 
printBook( &Book1 ); /* print Book2 info by passing address of Book2 */ printBook( &Book2 );
 return 0;
 }
 void printBook( struct Books *book ) { 
printf( "Book title : %s\n", book->title);
 printf( "Book author : %s\n", book->author);
 printf( "Book subject : %s\n", book->subject); 
printf( "Book book_id : %d\n", book->book_id); 
}

When the above code is compiled and executed, it produces the following result −

Book title : C Programming
Book author : Nuha Ali
Book subject : C Programming Tutorial
Book book_id : 6495407
Book title : Telecom Billing
Book author : Zara Ali
Book subject : Telecom Billing Tutorial
Book book_id : 6495700

Bit Fields

Bit Fields allow the packing of data in a structure. This is especially useful when memory or data storage is at a premium. Typical examples include −

  • Packing several objects into a machine word. e.g. 1 bit flags can be compacted.
  • Reading external file formats — non-standard file formats could be read in, e.g., 9-bit integers.

C allows us to do this in a structure definition by putting :bit length after the variable. For example −

struct packed_struct {
   unsigned int f1:1;
   unsigned int f2:1;
   unsigned int f3:1;
   unsigned int f4:1;
   unsigned int type:4;
   unsigned int my_int:9;
} pack;

Here, the packed_struct contains 6 members: Four 1 bit flags f1..f3, a 4-bit type and a 9-bit my_int.

C automatically packs the above bit fields as compactly as possible, provided that the maximum length of the field is less than or equal to the integer word length of the computer. If this is not the case, then some compilers may allow memory overlap for the fields while others would store the next field in the next word.

Chapter 4 Relational Algebra

Relational Algebra The part of mathematics in which letters and other general symbols are used to represent numbers and quantities in formula and equations. Ex: (x + y) · z = (x · z) + (y · z). The main application of relational algebra is providing a theoretical...

Chapter 3 Components of the Database System Environment

Components of the Database System Environment There are five major components in the database system environment and their interrelationships are. Hardware Software Data Users Procedures Hardware:  The hardware is the actual computer system used for keeping and...

Chapter 2: Database Languages and their information

Database Languages A DBMS must provide appropriate languages and interfaces for each category of users to express database queries and updates. Database Languages are used to create and maintain database on computer. There are large numbers of database languages like...

Database basic overview

What is DBMS? A Database Management System (DBMS) is a collection of interrelated data and a set of programs to access those data. Database management systems (DBMS) are computer software applications that interact with the user, other applications, and the database...

Laravel – Scopes (3 Easy Steps)

Scoping is one of the superpowers that eloquent grants to developers when querying a model. Scopes allow developers to add constraints to queries for a given model. In simple terms laravel scope is just a query, a query to make the code shorter and faster. We can...

CAMBRIDGE IELTS 17 TEST 3

READING PASSAGE 1: The thylacine Q1. carnivorous keywords: Looked like a dog had series of stripes ate, diet ate an entirely 1 .......................................... diet (2nd paragraph 3rd and 4th line) 1st and 2nd paragraph, 1st  paragraph,resemblance to a...

You may find interest following article

Chapter 4 Relational Algebra

Relational Algebra The part of mathematics in which letters and other general symbols are used to represent numbers and quantities in formula and equations. Ex: (x + y) · z = (x · z) + (y · z). The main application of relational algebra is providing a theoretical foundation for relational databases, particularly query languages for such databases. Relational algebra...

Chapter 3 Components of the Database System Environment

Components of the Database System Environment There are five major components in the database system environment and their interrelationships are. Hardware Software Data Users Procedures Hardware:  The hardware is the actual computer system used for keeping and accessing the database. Conventional DBMS hardware consists of secondary storage devices, usually...

Chapter 2: Database Languages and their information

Database Languages A DBMS must provide appropriate languages and interfaces for each category of users to express database queries and updates. Database Languages are used to create and maintain database on computer. There are large numbers of database languages like Oracle, MySQL, MS Access, dBase, FoxPro etc. Database Languages: Refers to the languages used to...

Database basic overview

What is DBMS? A Database Management System (DBMS) is a collection of interrelated data and a set of programs to access those data. Database management systems (DBMS) are computer software applications that interact with the user, other applications, and the database itself to capture and analyze data. Purpose of Database Systems The collection of data, usually...

Laravel – Scopes (3 Easy Steps)

Scoping is one of the superpowers that eloquent grants to developers when querying a model. Scopes allow developers to add constraints to queries for a given model. In simple terms laravel scope is just a query, a query to make the code shorter and faster. We can create custom query with relation or anything with scopes. In any admin project we need to get data...

CAMBRIDGE IELTS 17 TEST 3

READING PASSAGE 1: The thylacine Q1. carnivorous keywords: Looked like a dog had series of stripes ate, diet ate an entirely 1 .......................................... diet (2nd paragraph 3rd and 4th line) 1st and 2nd paragraph, 1st  paragraph,resemblance to a dog. … dark brown stripes over its back, beginning at the rear of the body and extending onto the...

CAMBRIDGE IELTS 17 TEST 4

PASSAGE 1 Q1 (False) (Many Madagascan forests are being destroyed by attacks from insects.) Madagascar's forests are being converted to agricultural land at a rate of one percent every year. Much of this destruction is fuelled by the cultivation of the country's main staple crop: rice. And a key reason for this destruction is that insect pests are destroying vast...

Cambridge IELTS 16 Test 4

Here we will discuss pros and cons of all the questions of the passage with step by step Solution included Tips and Strategies. Reading Passage 1 –Roman Tunnels IELTS Cambridge 16, Test 4, Academic Reading Module, Reading Passage 1 Questions 1-6. Label the diagrams below. The Persian Qanat Method 1. ………………………. to direct the tunnelingAnswer: posts – First...

Cambridge IELTS 16 Test 3

Reading Passage 1: Roman Shipbuilding and Navigation, Solution with Answer Key , Reading Passage 1: Roman Shipbuilding and Navigation IELTS Cambridge 16, Test 3, Academic Reading Module Cambridge IELTS 16, Test 3: Reading Passage 1 – Roman Shipbuilding and Navigation with Answer Key. Here we will discuss pros and cons of all the questions of the...

Cambridge IELTS 16 Test 2

Reading Passage 1: The White Horse of Uffington, Solution with Answer Key The White Horse of Uffington IELTS Cambridge 16, Test 2, Academic Reading Module, Reading Passage 1 Cambridge IELTS 16, Test 2: Reading Passage 1 – The White Horse of Uffington  with Answer Key. Here we will discuss pros and cons of all the questions of the passage with...

Cambridge IELTS 16 Test 1

Cambridge IELTS 16, Test 1, Reading Passage 1: Why We Need to Protect Bolar Bears, Solution with Answer Key Cambridge IELTS 16, Test 1: Reading Passage 1 – Why We Need to Protect Bolar Bears with Answer Key. Here we will discuss pros and cons of all the questions of the passage with step by step...

Cambridge IELTS 15 Reading Test 4 Answers

PASSAGE 1: THE RETURN OF THE HUARANGO QUESTIONS 1-5: COMPLETE THE NOTES BELOW. 1. Answer: water Key words:  access, deep, surface Paragraph 2 provides information on the role of the huarango tree: “it could reach deep water sources”. So the answer is ‘water’. access = reach Answer: water. 2. Answer: diet Key words: crucial,...

Cambridge IELTS 15 Reading Test 3 Answers

PASSAGE 1: HENRY MOORE (1898 – 1986 ) QUESTIONS 1-7: DO THE FOLLOWING STATEMENTS AGREE WITH THE INFORMATION GIVEN IN READING PASSAGE 1? 1. Answer: TRUE Key words: leaving school, Moore, did, father, wanted It is mentioned in the first paragraph that “After leaving school, Moore hoped to become a sculptor, but instead he complied with his father’s...

Cambridge IELTS 15 Reading Test 2 Answers 

PASSAGE 1: COULD URBAN ENGINEERS LEARN FROM DANCE ?  QUESTIONS 1- 6: READING PASSAGE 1 HAS SEVEN PARAGRAPHS, A-G. 1. Answer: B Key words: way of using dance, not proposing By using the skimming and scanning technique, we would find that before going into details about how engineers can learn from dance, the author first briefly mentions ways of...

Cambridge IELTS 15 Reading Test 1 Answers

PASSAGE 1: NUTMEG – A VALUABLE SPICE QUESTIONS 1- 4: COMPLETE THE NOTES BELOW.CHOOSE ONE WORD ONLY FROM THE PASSAGE FOR EACH ANSWER.WRITE YOUR ANSWER IN BOXES 1-8 ON YOUR ANSWER SHEET. 1. Answer: oval Key words: leaves, shape Using the scanning skill, we can see that the first paragraph describes the characteristics of the tree in detail, including...

CAMBRIDGE IELTS 14 READING TEST 4 ANSWERS 

PASSAGE 1: THE SECRET OF STAYING YOUNG QUESTIONS 1-8: COMPLETE THE NOTES BELOW. 1. ANSWER: FOUR / 4 Explain– Key words: focused age groups, ants– In paragraph 3, it is stated that “Giraldo focused on ants at four age ranges”,so the answer must be “four/4”. 2. ANSWER: YOUNG Explain– Key words: how well, ants, looked after– The first sentence of...

CAMBRIDGE IELTS 14 READING TEST 3 ANSWERS

PASSAGE 1: THE CONCEPT OF INTELLIGENCE QUESTIONS 1-3: READING PASSAGE 1 HAS SIX PARAGRAPHS, A-F. 1. ANSWER: B Explain ·     Key words: non-scientists, assumptions, intelligence, influence, behavior ·    People‟s behavior towards others‟ intelligence is mentioned in the first sentence of paragraph B: “implicit theories of...

CAMBRIDGE IELTS 14 READING TEST 2 ANSWERS

Cambridge IELTS 14 is the latest IELTS exam preparation.https://draftsbook.com/ will help you to answer all questions in cambridge ielts 14 reading test 2 with detail explanations. PASSAGE 1: ALEXANDER HENDERSON (1831-1913) QUESTIONS 1-8: DO THE FOLLOWING STATEMENTS AGREE WITH THE INFORMATION GIVEN IN READING PASSAGE 1? 1. ANSWER: FALSE Explain Henderson rarely...

Cambridge IELTS 14 Reading Test 1 Answers

Cambridge IELTS 14 is the latest IELTS exam preparation.https://draftsbook.com/ will help you to answer all questions in cambridge ielts 14 reading test 1 with detail explanations. PASSAGE 1: THE IMPORTANCE OF CHILDREN’S PLAY QUESTIONS 1-8: COMPLETE THE NOTES BELOW. 1. ANSWER: CREATIVITY Explain building a “magical kingdom” may help develop … – Key words: magical...

Cambridge IELTS 13 Reading Test 4 Answers 

PASSAGE 1: CUTTY SARK: THE FASTEST SAILING SHIP OF ALL TIME QUESTIONS 1-8: DO THE FOLLOWING STATEMENTS AGREE WITH THE INFORMATION GIVEN IN READING PASSAGE 1? 1. CLIPPERS WERE ORIGINALLY INTENDED TO BE USED AS PASSENGER SHIPS Key words: clippers, originally, passengerAt the beginning of paragraph 2, we find the statement: “The fastest commercial sailing...